想注册个短(心)点(伊)的用户名,还需要不断手动试?你已经Out了,直接上脚本按规则试错。
代码在: https://github.com/xyou365/gmail-username-available
代码运行环境是 Ubuntu 16.04 + Python3。(便宜VPS推荐: Virmach)
简单步骤:
1. 下载、运行脚本
git clone https://github.com/xyou365/gmail-username-available.git cd gmail-username-available/ python3 gmail_username_try.py
Mail okay [‘zzruer’, ‘zzbuhr’, ‘zzpyin’, ‘zzpacy’, ‘zzduci’, ‘zzsipe’, ‘zzpent’, ‘zzcuif’, ‘zzdrub’, ‘zztusk’, ‘zzbock’, ‘zznobs’, ‘zzbise’, ‘zzfugs’, ‘zzvast’, ‘zzfley’, ‘zzwhig’, ‘zzfrae’, ‘zzwabs’, ‘zzfeal’, ‘zzpeag’, ‘zzfuci’]
省事!
具体步骤补充:专属链接的获得
这里于验证的手机号,比正儿八经注册Google账号时的要求要低(经常美国IP+中国手机号无法注册),中国号码就可以,可以用各大接码平台
短用户名字典 words_raw.txt 是从 https://wordfinder.yourdictionary.com/letter-words/4/ 爬取
大佬,我运行老出错什么原因啊,请帮帮忙。
以下我截取部分片段。
yEYx3vSR9BMfGkNpxc-n_MWdkeho9_DETUOOizQJxUD1lbHLT9lS6diO5R1qC9pKJmJoUYg^&GmailAddress=qqqqqqqqq^&submit=Select”
zznowt
/bin/sh: 1: curl: not found
Traceback (most recent call last):
File “gmail_username_try.py”, line 89, in
main()
File “gmail_username_try.py”, line 69, in main
response = subprocess.check_output(curl_link, shell=True)
File “/usr/lib/python3.5/subprocess.py”, line 626, in check_output
**kwargs).stdout
File “/usr/lib/python3.5/subprocess.py”, line 708, in run
output=stdout, stderr=stderr)
subprocess.CalledProcessError: Command ‘curl -s “https://accounts.google.com/SignUpMobileUsername?hl=en^&dsh=-
******
******
最后一行是
R1qC9pKJmJoUYg^&GmailAddress=qqqqqqqqq^&submit=Select”‘ returned non-zero exit status 127
抱歉这么久才看到评论 🙂